Base | Representation |
---|---|
bin | 100010100100000111111111… |
… | …0001010010110111101111011 |
3 | 1110212111012000210000010100000 |
4 | 1011020033332022112331323 |
5 | 304322230232203012311 |
6 | 2554342231451044043 |
7 | 121016411133065055 |
oct | 10510177612267573 |
9 | 1425435023003300 |
10 | 304032114110331 |
11 | 88968328350542 |
12 | 2a123563a40623 |
13 | 1008514a583ba9 |
14 | 5511338ca08d5 |
15 | 252388dd46056 |
hex | 11483fe296f7b |
304032114110331 has 48 divisors (see below), whose sum is σ = 460553915858400. Its totient is φ = 200404495070208.
The previous prime is 304032114110297. The next prime is 304032114110339. The reversal of 304032114110331 is 133011411230403.
304032114110331 is a `hidden beast` number, since 3 + 0 + 4 + 0 + 3 + 211 + 4 + 110 + 331 = 666.
It is not a de Polignac number, because 304032114110331 - 27 = 304032114110203 is a prime.
It is a super-2 number, since 2×3040321141103312 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 304032114110295 and 304032114110304.
It is not an unprimeable number, because it can be changed into a prime (304032114110339) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 762303775 + ... + 762702503.
It is an arithmetic number, because the mean of its divisors is an integer number (9594873247050).
Almost surely, 2304032114110331 is an apocalyptic number.
304032114110331 is a deficient number, since it is larger than the sum of its proper divisors (156521801748069).
304032114110331 is an equidigital number, since it uses as much as digits as its factorization.
304032114110331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434090 (or 434078 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 304032114110331 its reverse (133011411230403), we get a palindrome (437043525340734).
The spelling of 304032114110331 in words is "three hundred four trillion, thirty-two billion, one hundred fourteen million, one hundred ten thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •