Base | Representation |
---|---|
bin | 100010101101101101101011… |
… | …1101100001111101110111010 |
3 | 1111001011011210011022001102110 |
4 | 1011123123113230033232322 |
5 | 310010323322023021132 |
6 | 3001231510410113150 |
7 | 121213545145215561 |
oct | 10533332754175672 |
9 | 1431134704261373 |
10 | 305350023642042 |
11 | 89326243983a05 |
12 | 2a2b6a6911b7b6 |
13 | 1014c4cac24772 |
14 | 555903cc46bd8 |
15 | 2547cc52041cc |
hex | 115b6d7b0fbba |
305350023642042 has 16 divisors (see below), whose sum is σ = 611015981113440. Its totient is φ = 101730685575792.
The previous prime is 305350023642031. The next prime is 305350023642107. The reversal of 305350023642042 is 240246320053503.
It is a super-3 number, since 3×3053500236420423 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13163896992 + ... + 13163920187.
It is an arithmetic number, because the mean of its divisors is an integer number (38188498819590).
Almost surely, 2305350023642042 is an apocalyptic number.
305350023642042 is an abundant number, since it is smaller than the sum of its proper divisors (305665957471398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
305350023642042 is a wasteful number, since it uses less digits than its factorization.
305350023642042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26327819117.
The product of its (nonzero) digits is 518400, while the sum is 39.
Adding to 305350023642042 its reverse (240246320053503), we get a palindrome (545596343695545).
The spelling of 305350023642042 in words is "three hundred five trillion, three hundred fifty billion, twenty-three million, six hundred forty-two thousand, forty-two".
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