Base | Representation |
---|---|
bin | 1001000001011011000… |
… | …00011011011101011010 |
3 | 1002122011111210121202020 |
4 | 10200231200123131122 |
5 | 20034340241333424 |
6 | 354225035515310 |
7 | 31253055024006 |
oct | 4405540333532 |
9 | 1078144717666 |
10 | 310001121114 |
11 | 10a51a607653 |
12 | 500b68b8b36 |
13 | 23304b1c459 |
14 | 1100b4b7706 |
15 | 80e56de079 |
hex | 482d81b75a |
310001121114 has 64 divisors (see below), whose sum is σ = 650273678208. Its totient is φ = 98411443200.
The previous prime is 310001121109. The next prime is 310001121149. The reversal of 310001121114 is 411121100013.
It is a super-2 number, since 2×3100011211142 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 310001121093 and 310001121102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20439694 + ... + 20454854.
It is an arithmetic number, because the mean of its divisors is an integer number (10160526222).
Almost surely, 2310001121114 is an apocalyptic number.
310001121114 is an abundant number, since it is smaller than the sum of its proper divisors (340272557094).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
310001121114 is a wasteful number, since it uses less digits than its factorization.
310001121114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17183.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 310001121114 its reverse (411121100013), we get a palindrome (721122221127).
The spelling of 310001121114 in words is "three hundred ten billion, one million, one hundred twenty-one thousand, one hundred fourteen".
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