Base | Representation |
---|---|
bin | 101101001010001100010… |
… | …111110100110001101001 |
3 | 101222200012210210102112021 |
4 | 231022030113310301221 |
5 | 401321100242142213 |
6 | 10333351324344441 |
7 | 440131125015121 |
oct | 55121427646151 |
9 | 11880183712467 |
10 | 3103321443433 |
11 | a97125062452 |
12 | 4215400a5121 |
13 | 1968464bc093 |
14 | aa2b7115c81 |
15 | 55ad0369d8d |
hex | 2d28c5f4c69 |
3103321443433 has 16 divisors (see below), whose sum is σ = 3227515494336. Its totient is φ = 2981466639360.
The previous prime is 3103321443427. The next prime is 3103321443457. The reversal of 3103321443433 is 3343441233013.
3103321443433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3103321443433 - 25 = 3103321443401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3103321443413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8285785 + ... + 8652217.
It is an arithmetic number, because the mean of its divisors is an integer number (201719718396).
Almost surely, 23103321443433 is an apocalyptic number.
It is an amenable number.
3103321443433 is a deficient number, since it is larger than the sum of its proper divisors (124194050903).
3103321443433 is a wasteful number, since it uses less digits than its factorization.
3103321443433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 369624.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 3103321443433 its reverse (3343441233013), we get a palindrome (6446762676446).
The spelling of 3103321443433 in words is "three trillion, one hundred three billion, three hundred twenty-one million, four hundred forty-three thousand, four hundred thirty-three".
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