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311001200313 = 3196189445269
BaseRepresentation
bin1001000011010010001…
…11011011011010111001
31002201202012121220111120
410201221013123122321
520043412301402223
6354512203015453
731316620404546
oct4415107333271
91081665556446
10311001200313
1110a993084991
125033580a589
13234340866ab
14110a4245bcd
1581533d8be3
hex48691db6b9

311001200313 has 16 divisors (see below), whose sum is σ = 443648539200. Its totient is φ = 193201778880.

The previous prime is 311001200269. The next prime is 311001200317. The reversal of 311001200313 is 313002100113.

It is not a de Polignac number, because 311001200313 - 214 = 311001183929 is a prime.

It is a super-2 number, since 2×3110012003132 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311001200292 and 311001200301.

It is not an unprimeable number, because it can be changed into a prime (311001200317) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44719158 + ... + 44726111.

It is an arithmetic number, because the mean of its divisors is an integer number (27728033700).

Almost surely, 2311001200313 is an apocalyptic number.

It is an amenable number.

311001200313 is a deficient number, since it is larger than the sum of its proper divisors (132647338887).

311001200313 is a wasteful number, since it uses less digits than its factorization.

311001200313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89445352.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 311001200313 its reverse (313002100113), we get a palindrome (624003300426).

The spelling of 311001200313 in words is "three hundred eleven billion, one million, two hundred thousand, three hundred thirteen".

Divisors: 1 3 19 57 61 183 1159 3477 89445269 268335807 1699460111 5098380333 5456161409 16368484227 103667066771 311001200313