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31102423113 = 350985723767
BaseRepresentation
bin11100111101110110…
…010101000001001001
32222021120200210120210
4130331312111001021
51002144210014423
622142132511333
72150514143256
oct347566250111
988246623523
1031102423113
1112210563913
12604017b549
132c188b3978
141710a1842d
15c207dcb93
hex73dd95049

31102423113 has 16 divisors (see below), whose sum is σ = 41601605760. Its totient is φ = 20669195136.

The previous prime is 31102423111. The next prime is 31102423127. The reversal of 31102423113 is 31132420113.

It is not a de Polignac number, because 31102423113 - 21 = 31102423111 is a prime.

It is a super-2 number, since 2×311024231132 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 31102423113.

It is not an unprimeable number, because it can be changed into a prime (31102423111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1296756 + ... + 1320522.

It is an arithmetic number, because the mean of its divisors is an integer number (2600100360).

Almost surely, 231102423113 is an apocalyptic number.

It is an amenable number.

31102423113 is a deficient number, since it is larger than the sum of its proper divisors (10499182647).

31102423113 is a wasteful number, since it uses less digits than its factorization.

31102423113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25136.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 31102423113 its reverse (31132420113), we get a palindrome (62234843226).

The spelling of 31102423113 in words is "thirty-one billion, one hundred two million, four hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 3 509 857 1527 2571 23767 71301 436213 1308639 12097403 20368319 36292209 61104957 10367474371 31102423113