31113011113131 has 32 divisors (see below), whose sum is σ = 42411659696640. Its totient is φ = 20281956710400.

The previous prime is 31113011113103. The next prime is 31113011113147. The reversal of 31113011113131 is 13131111031113.

It is not a de Polignac number, because 31113011113131 - 2²³ = 31113002724523 is a prime.

It is a super-2 number, since 2×31113011113131² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31113011113098 and 31113011113107.

It is not an unprimeable number, because it can be changed into a prime (31113011113031) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 259256161 + ... + 259376141.

It is an arithmetic number, because the mean of its divisors is an integer number (1325364365520).

Almost surely, 2^{31113011113131} is an apocalyptic number.

31113011113131 is a deficient number, since it is larger than the sum of its proper divisors (11298648583509).

31113011113131 is a wasteful number, since it uses less digits than its factorization.

31113011113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127827.

The product of its (nonzero) digits is 81, while the sum is 21.

Adding to 31113011113131 its reverse (13131111031113), we get a palindrome (44244122144244).

The spelling of 31113011113131 in words is "thirty-one trillion, one hundred thirteen billion, eleven million, one hundred thirteen thousand, one hundred thirty-one".