Base | Representation |
---|---|
bin | 1110001100010101001100… |
… | …01010101110011000011011 |
3 | 11002111122111222011212112120 |
4 | 13012022212022232120123 |
5 | 13042321110132431021 |
6 | 150213404011312323 |
7 | 6400564252404210 |
oct | 706124612563033 |
9 | 132448458155476 |
10 | 31210020202011 |
11 | 9a43105840232 |
12 | 360086474b6a3 |
13 | 1455127968771 |
14 | 79c8045b5b07 |
15 | 391c9e5132c6 |
hex | 1c62a62ae61b |
31210020202011 has 16 divisors (see below), whose sum is σ = 47743177104384. Its totient is φ = 17764903102464.
The previous prime is 31210020201979. The next prime is 31210020202061. The reversal of 31210020202011 is 11020202001213.
It is not a de Polignac number, because 31210020202011 - 25 = 31210020201979 is a prime.
It is a super-2 number, since 2×312100202020112 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31210020202061) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2891417635 + ... + 2891428428.
It is an arithmetic number, because the mean of its divisors is an integer number (2983948569024).
Almost surely, 231210020202011 is an apocalyptic number.
31210020202011 is a deficient number, since it is larger than the sum of its proper divisors (16533156902373).
31210020202011 is a wasteful number, since it uses less digits than its factorization.
31210020202011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5782846330.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 31210020202011 its reverse (11020202001213), we get a palindrome (42230222203224).
The spelling of 31210020202011 in words is "thirty-one trillion, two hundred ten billion, twenty million, two hundred two thousand, eleven".
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