Base | Representation |
---|---|
bin | 1110001100011101011100… |
… | …10110010001001111011011 |
3 | 11002112001221212011112120001 |
4 | 13012032232112101033123 |
5 | 13042404144304212103 |
6 | 150215415501113431 |
7 | 6401112141521260 |
oct | 706165626211733 |
9 | 132461855145501 |
10 | 31214452413403 |
11 | 9a44a7a6a0256 |
12 | 36016a0b58877 |
13 | 1455682c9915c |
14 | 79cb050b7267 |
15 | 391e5d6b101d |
hex | 1c63ae5913db |
31214452413403 has 16 divisors (see below), whose sum is σ = 35805373757440. Its totient is φ = 26656475335776.
The previous prime is 31214452413371. The next prime is 31214452413457. The reversal of 31214452413403 is 30431425441213.
It is a cyclic number.
It is not a de Polignac number, because 31214452413403 - 25 = 31214452413371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31214462413403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23280958 + ... + 24585196.
It is an arithmetic number, because the mean of its divisors is an integer number (2237835859840).
Almost surely, 231214452413403 is an apocalyptic number.
31214452413403 is a deficient number, since it is larger than the sum of its proper divisors (4590921344037).
31214452413403 is a wasteful number, since it uses less digits than its factorization.
31214452413403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1316866.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 31214452413403 its reverse (30431425441213), we get a palindrome (61645877854616).
The spelling of 31214452413403 in words is "thirty-one trillion, two hundred fourteen billion, four hundred fifty-two million, four hundred thirteen thousand, four hundred three".
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