Base | Representation |
---|---|
bin | 1110001100101001111000… |
… | …11111010000100101110011 |
3 | 11002112201012101011212201010 |
4 | 13012110330133100211303 |
5 | 13043011334304231003 |
6 | 150222442354042003 |
7 | 6401436521114124 |
oct | 706247437204563 |
9 | 132481171155633 |
10 | 31221132102003 |
11 | 9a47898158158 |
12 | 3602a45b79303 |
13 | 14561a8b1220c |
14 | 79d17a29404b |
15 | 3921eed08003 |
hex | 1c653c7d0973 |
31221132102003 has 16 divisors (see below), whose sum is σ = 42984798105600. Its totient is φ = 20136207632640.
The previous prime is 31221132101963. The next prime is 31221132102053. The reversal of 31221132102003 is 30020123112213.
It is not a de Polignac number, because 31221132102003 - 210 = 31221132100979 is a prime.
It is a super-3 number, since 3×312211321020033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (31221132102053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53527038 + ... + 54107171.
It is an arithmetic number, because the mean of its divisors is an integer number (2686549881600).
Almost surely, 231221132102003 is an apocalyptic number.
31221132102003 is a deficient number, since it is larger than the sum of its proper divisors (11763666003597).
31221132102003 is a wasteful number, since it uses less digits than its factorization.
31221132102003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107637362.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 31221132102003 its reverse (30020123112213), we get a palindrome (61241255214216).
The spelling of 31221132102003 in words is "thirty-one trillion, two hundred twenty-one billion, one hundred thirty-two million, one hundred two thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •