Base | Representation |
---|---|
bin | 101101100011010001101… |
… | …111111111111110010001 |
3 | 102002020201212102122201021 |
4 | 231203101233333332101 |
5 | 402241230313244213 |
6 | 10354004104435441 |
7 | 442103433203026 |
oct | 55432157777621 |
9 | 12066655378637 |
10 | 3130255212433 |
11 | aa7596509778 |
12 | 4267b8178b81 |
13 | 1992495507bb |
14 | ab71023754d |
15 | 56659bbad8d |
hex | 2d8d1bfff91 |
3130255212433 has 16 divisors (see below), whose sum is σ = 3156144571216. Its totient is φ = 3104467845120.
The previous prime is 3130255212431. The next prime is 3130255212457. The reversal of 3130255212433 is 3342125520313.
It can be written as a sum of positive squares in 8 ways, for example, as 28880623249 + 3101374589184 = 169943^2 + 1761072^2 .
It is a cyclic number.
It is not a de Polignac number, because 3130255212433 - 21 = 3130255212431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3130255212431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169808785 + ... + 169827217.
It is an arithmetic number, because the mean of its divisors is an integer number (197259035701).
Almost surely, 23130255212433 is an apocalyptic number.
It is an amenable number.
3130255212433 is a deficient number, since it is larger than the sum of its proper divisors (25889358783).
3130255212433 is a wasteful number, since it uses less digits than its factorization.
3130255212433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21124.
The product of its (nonzero) digits is 64800, while the sum is 34.
The spelling of 3130255212433 in words is "three trillion, one hundred thirty billion, two hundred fifty-five million, two hundred twelve thousand, four hundred thirty-three".
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