Base | Representation |
---|---|
bin | 101101100100111010100… |
… | …001011011011010000011 |
3 | 102002102021101000112101110 |
4 | 231210322201123122003 |
5 | 402303330312002243 |
6 | 10354454340134403 |
7 | 442165126150044 |
oct | 55447241333203 |
9 | 12072241015343 |
10 | 3132013000323 |
11 | aa8308761839 |
12 | 427008997403 |
13 | 19946978118c |
14 | ab8398828cb |
15 | 5670e186e33 |
hex | 2d93a85b683 |
3132013000323 has 16 divisors (see below), whose sum is σ = 4368557469600. Its totient is φ = 1993356583680.
The previous prime is 3132013000301. The next prime is 3132013000327. The reversal of 3132013000323 is 3230003102313.
3132013000323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3132013000323 - 210 = 3132012999299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3132013000323.
It is not an unprimeable number, because it can be changed into a prime (3132013000327) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 202240288 + ... + 202255773.
It is an arithmetic number, because the mean of its divisors is an integer number (273034841850).
Almost surely, 23132013000323 is an apocalyptic number.
3132013000323 is a deficient number, since it is larger than the sum of its proper divisors (1236544469277).
3132013000323 is a wasteful number, since it uses less digits than its factorization.
3132013000323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 404496182.
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 3132013000323 its reverse (3230003102313), we get a palindrome (6362016102636).
The spelling of 3132013000323 in words is "three trillion, one hundred thirty-two billion, thirteen million, three hundred twenty-three", and thus it is an aban number.
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