Base | Representation |
---|---|
bin | 11101010111111100… |
… | …010111110100001011 |
3 | 10000102002110221020000 |
4 | 131113330113310023 |
5 | 1004043243340201 |
6 | 22253412134043 |
7 | 2164411255512 |
oct | 352774276413 |
9 | 100362427200 |
10 | 31540215051 |
11 | 124156a1434 |
12 | 6142907323 |
13 | 2c884c7a57 |
14 | 1752c19679 |
15 | c48e68d86 |
hex | 757f17d0b |
31540215051 has 20 divisors (see below), whose sum is σ = 47779239024. Its totient is φ = 20730654000.
The previous prime is 31540215037. The next prime is 31540215121. The reversal of 31540215051 is 15051204513.
31540215051 is a `hidden beast` number, since 3 + 1 + 540 + 21 + 50 + 51 = 666.
It is not a de Polignac number, because 31540215051 - 29 = 31540214539 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (31540215001) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2736400 + ... + 2747901.
Almost surely, 231540215051 is an apocalyptic number.
31540215051 is a deficient number, since it is larger than the sum of its proper divisors (16239023973).
31540215051 is an equidigital number, since it uses as much as digits as its factorization.
31540215051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5484384 (or 5484375 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 31540215051 its reverse (15051204513), we get a palindrome (46591419564).
The spelling of 31540215051 in words is "thirty-one billion, five hundred forty million, two hundred fifteen thousand, fifty-one".
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