Base | Representation |
---|---|
bin | 101101111011101011000… |
… | …101101100100001111001 |
3 | 102011202100102210112221121 |
4 | 231323223011230201321 |
5 | 403203402213243022 |
6 | 10414015252505241 |
7 | 444021530312116 |
oct | 55735305544171 |
9 | 12152312715847 |
10 | 3156450134137 |
11 | 10077088a30a3 |
12 | 42b8a891b221 |
13 | 19b8624c0b81 |
14 | acab718b90d |
15 | 5718e7242c7 |
hex | 2deeb16c879 |
3156450134137 has 16 divisors (see below), whose sum is σ = 3199498646400. Its totient is φ = 3113731387008.
The previous prime is 3156450134029. The next prime is 3156450134221. The reversal of 3156450134137 is 7314310546513.
It is not a de Polignac number, because 3156450134137 - 219 = 3156449609849 is a prime.
It is a super-4 number, since 4×31564501341374 (a number of 51 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3156450134093 and 3156450134102.
It is not an unprimeable number, because it can be changed into a prime (3156450194137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21655978 + ... + 21801244.
It is an arithmetic number, because the mean of its divisors is an integer number (199968665400).
Almost surely, 23156450134137 is an apocalyptic number.
It is an amenable number.
3156450134137 is a deficient number, since it is larger than the sum of its proper divisors (43048512263).
3156450134137 is a wasteful number, since it uses less digits than its factorization.
3156450134137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146400.
The product of its (nonzero) digits is 453600, while the sum is 43.
The spelling of 3156450134137 in words is "three trillion, one hundred fifty-six billion, four hundred fifty million, one hundred thirty-four thousand, one hundred thirty-seven".
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