Base | Representation |
---|---|
bin | 1110100011010101001110… |
… | …01100000100001011101011 |
3 | 11012022012101201022221210011 |
4 | 13101222213030010023223 |
5 | 13143243114144010011 |
6 | 152020423504432351 |
7 | 6511642355122600 |
oct | 721524714041353 |
9 | 135265351287704 |
10 | 32000311313131 |
11 | a21828a543017 |
12 | 3709a5b6186b7 |
13 | 14b1802332875 |
14 | 7c8b753166a7 |
15 | 3a760529c621 |
hex | 1d1aa73042eb |
32000311313131 has 48 divisors (see below), whose sum is σ = 37895713488864. Its totient is φ = 26937882671616.
The previous prime is 32000311313059. The next prime is 32000311313219. The reversal of 32000311313131 is 13131311300023.
It is not a de Polignac number, because 32000311313131 - 219 = 32000310788843 is a prime.
It is a super-2 number, since 2×320003113131312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (32000311313431) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1296439116 + ... + 1296463798.
It is an arithmetic number, because the mean of its divisors is an integer number (789494031018).
Almost surely, 232000311313131 is an apocalyptic number.
32000311313131 is a deficient number, since it is larger than the sum of its proper divisors (5895402175733).
32000311313131 is a wasteful number, since it uses less digits than its factorization.
32000311313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26300 (or 26293 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 32000311313131 its reverse (13131311300023), we get a palindrome (45131622613154).
The spelling of 32000311313131 in words is "thirty-two trillion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty-one".
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