Base | Representation |
---|---|
bin | 1110101001011111100010… |
… | …00011110001010010000011 |
3 | 11020001102210221120012220221 |
4 | 13110233301003301102003 |
5 | 13210230141014100201 |
6 | 152301553530443511 |
7 | 6533145326523610 |
oct | 724576103612203 |
9 | 136042727505827 |
10 | 32212004050051 |
11 | a29a041580561 |
12 | 3742a9ab93597 |
13 | 14c876ac44887 |
14 | 7d50d82b1507 |
15 | 3acd94eeb4a1 |
hex | 1d4bf10f1483 |
32212004050051 has 16 divisors (see below), whose sum is σ = 37677371108608. Its totient is φ = 26962806376800.
The previous prime is 32212004050021. The next prime is 32212004050117. The reversal of 32212004050051 is 15005040021223.
It is not a de Polignac number, because 32212004050051 - 25 = 32212004050019 is a prime.
It is a super-2 number, since 2×322120040500512 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32212004049998 and 32212004050025.
It is not an unprimeable number, because it can be changed into a prime (32212004050021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9169860 + ... + 12186481.
It is an arithmetic number, because the mean of its divisors is an integer number (2354835694288).
Almost surely, 232212004050051 is an apocalyptic number.
32212004050051 is a deficient number, since it is larger than the sum of its proper divisors (5465367058557).
32212004050051 is a wasteful number, since it uses less digits than its factorization.
32212004050051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21361402.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 32212004050051 its reverse (15005040021223), we get a palindrome (47217044071274).
The spelling of 32212004050051 in words is "thirty-two trillion, two hundred twelve billion, four million, fifty thousand, fifty-one".
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