Base | Representation |
---|---|
bin | 101110111010101101110… |
… | …111110000000010011011 |
3 | 102102020002001000022200202 |
4 | 232322231313300002123 |
5 | 410311020442420201 |
6 | 10505052312052415 |
7 | 451636154311601 |
oct | 56725567600233 |
9 | 12366061008622 |
10 | 3224142545051 |
11 | 103339546034a |
12 | 440a3a99410b |
13 | 1a505c836c9c |
14 | b209951b871 |
15 | 58d02464c6b |
hex | 2eeaddf009b |
3224142545051 has 16 divisors (see below), whose sum is σ = 3291989299200. Its totient is φ = 3156972907200.
The previous prime is 3224142545033. The next prime is 3224142545053. The reversal of 3224142545051 is 1505452414223.
It is a cyclic number.
It is not a de Polignac number, because 3224142545051 - 210 = 3224142544027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3224142544996 and 3224142545014.
It is not an unprimeable number, because it can be changed into a prime (3224142545053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8202215 + ... + 8586303.
It is an arithmetic number, because the mean of its divisors is an integer number (205749331200).
Almost surely, 23224142545051 is an apocalyptic number.
3224142545051 is a deficient number, since it is larger than the sum of its proper divisors (67846754149).
3224142545051 is a wasteful number, since it uses less digits than its factorization.
3224142545051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 384970.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 3224142545051 its reverse (1505452414223), we get a palindrome (4729594959274).
The spelling of 3224142545051 in words is "three trillion, two hundred twenty-four billion, one hundred forty-two million, five hundred forty-five thousand, fifty-one".
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