Base | Representation |
---|---|
bin | 100101101001010010111100… |
… | …1011100110000001010000011 |
3 | 1121102102211022212112221022020 |
4 | 1023102211321130300022003 |
5 | 321400223024041401011 |
6 | 3132131312554412523 |
7 | 126514302055553253 |
oct | 11322457134601203 |
9 | 1542384285487266 |
10 | 331131131200131 |
11 | 96565a18a9aa39 |
12 | 3117b521a31143 |
13 | 1129c6bb16a3c2 |
14 | 5baab91a35963 |
15 | 28437321ad006 |
hex | 12d2979730283 |
331131131200131 has 16 divisors (see below), whose sum is σ = 443842940486400. Its totient is φ = 219587285348640.
The previous prime is 331131131200127. The next prime is 331131131200139. The reversal of 331131131200131 is 131002131131133.
It is not a de Polignac number, because 331131131200131 - 22 = 331131131200127 is a prime.
It is a super-2 number, since 2×3311311312001312 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (331131131200139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70299145 + ... + 74861418.
It is an arithmetic number, because the mean of its divisors is an integer number (27740183780400).
Almost surely, 2331131131200131 is an apocalyptic number.
331131131200131 is a deficient number, since it is larger than the sum of its proper divisors (112711809286269).
331131131200131 is a wasteful number, since it uses less digits than its factorization.
331131131200131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145164586.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 331131131200131 its reverse (131002131131133), we get a palindrome (462133262331264).
The spelling of 331131131200131 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred thousand, one hundred thirty-one".
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