Base | Representation |
---|---|
bin | 110000001100111010011… |
… | …111100010011001101001 |
3 | 102201122212221010000222120 |
4 | 300030322133202121221 |
5 | 413232244142143423 |
6 | 11013410203541453 |
7 | 461212250025564 |
oct | 60147237423151 |
9 | 12648787100876 |
10 | 3312401131113 |
11 | 10678660a2368 |
12 | 455b7052a889 |
13 | 1b048693c6c9 |
14 | b646d0334db |
15 | 5b26a9abee3 |
hex | 3033a7e2669 |
3312401131113 has 16 divisors (see below), whose sum is σ = 4419794384640. Its totient is φ = 2206638253904.
The previous prime is 3312401131003. The next prime is 3312401131133. The reversal of 3312401131113 is 3111311042133.
3312401131113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3312401131113 - 222 = 3312396936809 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3312401131133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22670470 + ... + 22816112.
It is an arithmetic number, because the mean of its divisors is an integer number (276237149040).
Almost surely, 23312401131113 is an apocalyptic number.
It is an amenable number.
3312401131113 is a deficient number, since it is larger than the sum of its proper divisors (1107393253527).
3312401131113 is a wasteful number, since it uses less digits than its factorization.
3312401131113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151188.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 3312401131113 its reverse (3111311042133), we get a palindrome (6423712173246).
The spelling of 3312401131113 in words is "three trillion, three hundred twelve billion, four hundred one million, one hundred thirty-one thousand, one hundred thirteen".
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