Base | Representation |
---|---|
bin | 110000010101000010011… |
… | …010101001001010011011 |
3 | 102202111101211201201010211 |
4 | 300111002122221022123 |
5 | 413403130221003121 |
6 | 11021411525151551 |
7 | 461641356136450 |
oct | 60250232511233 |
9 | 12674354651124 |
10 | 3321124000411 |
11 | 1070531a0a158 |
12 | 4577a585b5b7 |
13 | 1b1246b6b329 |
14 | b6a59709827 |
15 | 5b5cb695ce1 |
hex | 305426a929b |
3321124000411 has 16 divisors (see below), whose sum is σ = 3844050048000. Its totient is φ = 2810326042368.
The previous prime is 3321124000409. The next prime is 3321124000421. The reversal of 3321124000411 is 1140004211233.
It is a cyclic number.
It is not a de Polignac number, because 3321124000411 - 21 = 3321124000409 is a prime.
It is a super-2 number, since 2×33211240004112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3321124000421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4621515 + ... + 5291563.
It is an arithmetic number, because the mean of its divisors is an integer number (240253128000).
Almost surely, 23321124000411 is an apocalyptic number.
3321124000411 is a deficient number, since it is larger than the sum of its proper divisors (522926047589).
3321124000411 is an equidigital number, since it uses as much as digits as its factorization.
3321124000411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 679098.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 3321124000411 its reverse (1140004211233), we get a palindrome (4461128211644).
The spelling of 3321124000411 in words is "three trillion, three hundred twenty-one billion, one hundred twenty-four million, four hundred eleven", and thus it is an aban number.
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