Base | Representation |
---|---|
bin | 1001101011011000000… |
… | …11111000110010000011 |
3 | 1011210022021021120200220 |
4 | 10311230003320302003 |
5 | 20422003003041011 |
6 | 412432102114123 |
7 | 33011201414403 |
oct | 4655403706203 |
9 | 1153267246626 |
10 | 332525440131 |
11 | 119028a3a935 |
12 | 5454211b943 |
13 | 2548448c781 |
14 | 12146b40803 |
15 | 89b2d8b506 |
hex | 4d6c0f8c83 |
332525440131 has 16 divisors (see below), whose sum is σ = 465426539520. Its totient is φ = 210896393760.
The previous prime is 332525440111. The next prime is 332525440147. The reversal of 332525440131 is 131044525233.
It is not a de Polignac number, because 332525440131 - 27 = 332525440003 is a prime.
It is a super-2 number, since 2×3325254401312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332525440092 and 332525440101.
It is not an unprimeable number, because it can be changed into a prime (332525440111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30295720 + ... + 30306693.
It is an arithmetic number, because the mean of its divisors is an integer number (29089158720).
Almost surely, 2332525440131 is an apocalyptic number.
332525440131 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
332525440131 is a deficient number, since it is larger than the sum of its proper divisors (132901099389).
332525440131 is a wasteful number, since it uses less digits than its factorization.
332525440131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60602506.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 332525440131 its reverse (131044525233), we get a palindrome (463569965364).
The spelling of 332525440131 in words is "three hundred thirty-two billion, five hundred twenty-five million, four hundred forty thousand, one hundred thirty-one".
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