Base | Representation |
---|---|
bin | 110000011110011101011… |
… | …000001111010011001010 |
3 | 102210110111211211022220111 |
4 | 300132131120033103022 |
5 | 414034334422001214 |
6 | 11030203414544534 |
7 | 462450143032330 |
oct | 60363530172312 |
9 | 12713454738814 |
10 | 3331240031434 |
11 | 1074853174a77 |
12 | 45974966814a |
13 | 1b21998c2cc3 |
14 | b7339033b50 |
15 | 5b9be8235c4 |
hex | 3079d60f4ca |
3331240031434 has 16 divisors (see below), whose sum is σ = 5717756174400. Its totient is φ = 1425909554784.
The previous prime is 3331240031417. The next prime is 3331240031503. The reversal of 3331240031434 is 4341300421333.
3331240031434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×33312400314342 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3331240031396 and 3331240031405.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 147050304 + ... + 147072955.
It is an arithmetic number, because the mean of its divisors is an integer number (357359760900).
Almost surely, 23331240031434 is an apocalyptic number.
3331240031434 is a deficient number, since it is larger than the sum of its proper divisors (2386516142966).
3331240031434 is a wasteful number, since it uses less digits than its factorization.
3331240031434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 294124077.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 3331240031434 its reverse (4341300421333), we get a palindrome (7672540452767).
The spelling of 3331240031434 in words is "three trillion, three hundred thirty-one billion, two hundred forty million, thirty-one thousand, four hundred thirty-four".
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