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3331240031434 = 27809294123259
BaseRepresentation
bin110000011110011101011…
…000001111010011001010
3102210110111211211022220111
4300132131120033103022
5414034334422001214
611030203414544534
7462450143032330
oct60363530172312
912713454738814
103331240031434
111074853174a77
1245974966814a
131b21998c2cc3
14b7339033b50
155b9be8235c4
hex3079d60f4ca

3331240031434 has 16 divisors (see below), whose sum is σ = 5717756174400. Its totient is φ = 1425909554784.

The previous prime is 3331240031417. The next prime is 3331240031503. The reversal of 3331240031434 is 4341300421333.

3331240031434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×33312400314342 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3331240031396 and 3331240031405.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 147050304 + ... + 147072955.

It is an arithmetic number, because the mean of its divisors is an integer number (357359760900).

Almost surely, 23331240031434 is an apocalyptic number.

3331240031434 is a deficient number, since it is larger than the sum of its proper divisors (2386516142966).

3331240031434 is a wasteful number, since it uses less digits than its factorization.

3331240031434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 294124077.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 3331240031434 its reverse (4341300421333), we get a palindrome (7672540452767).

The spelling of 3331240031434 in words is "three trillion, three hundred thirty-one billion, two hundred forty million, thirty-one thousand, four hundred thirty-four".

Divisors: 1 2 7 14 809 1618 5663 11326 294123259 588246518 2058862813 4117725626 237945716531 475891433062 1665620015717 3331240031434