Base | Representation |
---|---|
bin | 110000100110111111011… |
… | …100001000111000100011 |
3 | 102211100011022120202201120 |
4 | 300212333130020320203 |
5 | 414212120230214132 |
6 | 11034320443103323 |
7 | 463223155350453 |
oct | 60467734107043 |
9 | 12740138522646 |
10 | 3340401413667 |
11 | 107872457204a |
12 | 45b485811b43 |
13 | 1b2cc9928c36 |
14 | b7967a57d63 |
15 | 5bd58c7c02c |
hex | 309bf708e23 |
3340401413667 has 16 divisors (see below), whose sum is σ = 4553071810560. Its totient is φ = 2177727879200.
The previous prime is 3340401413599. The next prime is 3340401413669. The reversal of 3340401413667 is 7663141040433.
3340401413667 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3340401413667 - 210 = 3340401412643 is a prime.
It is a super-2 number, since 2×33404014136672 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3340401413669) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49370184 + ... + 49437797.
It is an arithmetic number, because the mean of its divisors is an integer number (284566988160).
Almost surely, 23340401413667 is an apocalyptic number.
3340401413667 is a deficient number, since it is larger than the sum of its proper divisors (1212670396893).
3340401413667 is a wasteful number, since it uses less digits than its factorization.
3340401413667 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98808234.
The product of its (nonzero) digits is 435456, while the sum is 42.
The spelling of 3340401413667 in words is "three trillion, three hundred forty billion, four hundred one million, four hundred thirteen thousand, six hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •