3400204775211 has 10 divisors (see below), whose sum is σ = 5079318244572. Its totient is φ = 2266803183420.

The previous prime is 3400204775161. The next prime is 3400204775213. The reversal of 3400204775211 is 1125774020043.

3400204775211 is a `hidden beast` number, since 3 + 40 + 0 + 20 + 4 + 77 + 521 + 1 = 666.

It is not a de Polignac number, because 3400204775211 - 2¹⁴ = 3400204758827 is a prime.

It is a super-3 number, since 3×3400204775211³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (3400204775213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 20988918285 + ... + 20988918446.

Almost surely, 2^{3400204775211} is an apocalyptic number.

3400204775211 is a deficient number, since it is larger than the sum of its proper divisors (1679113469361).

3400204775211 is an equidigital number, since it uses as much as digits as its factorization.

3400204775211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41977836743 (or 41977836734 counting only the distinct ones).

The product of its (nonzero) digits is 47040, while the sum is 36.

Adding to 3400204775211 its reverse (1125774020043), we get a palindrome (4525978795254).

The spelling of 3400204775211 in words is "three trillion, four hundred billion, two hundred four million, seven hundred seventy-five thousand, two hundred eleven".