Base | Representation |
---|---|
bin | 110001111101010100111… |
… | …000101011001001010010 |
3 | 110011012102211222220122111 |
4 | 301331110320223021102 |
5 | 422221443332344214 |
6 | 11145051252055534 |
7 | 503014331056324 |
oct | 61752470531122 |
9 | 13135384886574 |
10 | 3433103012434 |
11 | 1103a75171297 |
12 | 4754373045aa |
13 | 1bb981374564 |
14 | bc23d683614 |
15 | 5e4823a75c4 |
hex | 31f54e2b252 |
3433103012434 has 16 divisors (see below), whose sum is σ = 5151120984000. Its totient is φ = 1716062768784.
The previous prime is 3433103012431. The next prime is 3433103012473. The reversal of 3433103012434 is 4342103013343.
3433103012434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3433103012396 and 3433103012405.
It is not an unprimeable number, because it can be changed into a prime (3433103012431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132955177 + ... + 132980995.
It is an arithmetic number, because the mean of its divisors is an integer number (321945061500).
Almost surely, 23433103012434 is an apocalyptic number.
3433103012434 is a deficient number, since it is larger than the sum of its proper divisors (1718017971566).
3433103012434 is a wasteful number, since it uses less digits than its factorization.
3433103012434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42177.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 3433103012434 its reverse (4342103013343), we get a palindrome (7775206025777).
Subtracting 3433103012434 from its reverse (4342103013343), we obtain a palindrome (909000000909).
The spelling of 3433103012434 in words is "three trillion, four hundred thirty-three billion, one hundred three million, twelve thousand, four hundred thirty-four".
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