Base | Representation |
---|---|
bin | 110001111101011100100… |
… | …101101100010111000001 |
3 | 110011012202212012002022000 |
4 | 301331130211230113001 |
5 | 422222224424120101 |
6 | 11145112150134213 |
7 | 503020460442135 |
oct | 61753445542701 |
9 | 13135685162260 |
10 | 3433232254401 |
11 | 1104031115734 |
12 | 475472651369 |
13 | 1bb9a2085cb1 |
14 | bc2528c73c5 |
15 | 5e48d8d6486 |
hex | 31f5c96c5c1 |
3433232254401 has 16 divisors (see below), whose sum is σ = 5086322222400. Its totient is φ = 2288798005824.
The previous prime is 3433232254297. The next prime is 3433232254427. The reversal of 3433232254401 is 1044522323343.
3433232254401 is a `hidden beast` number, since 3 + 4 + 3 + 3 + 23 + 225 + 4 + 401 = 666.
It is not a de Polignac number, because 3433232254401 - 29 = 3433232253889 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3433232254201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2262825 + ... + 3462201.
It is an arithmetic number, because the mean of its divisors is an integer number (317895138900).
Almost surely, 23433232254401 is an apocalyptic number.
It is an amenable number.
3433232254401 is a deficient number, since it is larger than the sum of its proper divisors (1653089967999).
3433232254401 is a wasteful number, since it uses less digits than its factorization.
3433232254401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1305405 (or 1305399 counting only the distinct ones).
The product of its (nonzero) digits is 207360, while the sum is 36.
Adding to 3433232254401 its reverse (1044522323343), we get a palindrome (4477754577744).
The spelling of 3433232254401 in words is "three trillion, four hundred thirty-three billion, two hundred thirty-two million, two hundred fifty-four thousand, four hundred one".
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