Base | Representation |
---|---|
bin | 110011011000111001000… |
… | …010101001000101101011 |
3 | 110111121012201222000102021 |
4 | 303120321002221011223 |
5 | 430324322022024321 |
6 | 11302151220445311 |
7 | 513064611446266 |
oct | 63307102510553 |
9 | 13447181860367 |
10 | 3531420111211 |
11 | 1141737652833 |
12 | 4904b5549837 |
13 | 1c801c313455 |
14 | c2cc8dcdcdd |
15 | 61cd89b9941 |
hex | 336390a916b |
3531420111211 has 16 divisors (see below), whose sum is σ = 3687285888000. Its totient is φ = 3378312966240.
The previous prime is 3531420111187. The next prime is 3531420111229. The reversal of 3531420111211 is 1121110241353.
It is a cyclic number.
It is not a de Polignac number, because 3531420111211 - 211 = 3531420109163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3531420111511) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 409165 + ... + 2688913.
It is an arithmetic number, because the mean of its divisors is an integer number (230455368000).
Almost surely, 23531420111211 is an apocalyptic number.
3531420111211 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
3531420111211 is a deficient number, since it is larger than the sum of its proper divisors (155865776789).
3531420111211 is a wasteful number, since it uses less digits than its factorization.
3531420111211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2280354.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 3531420111211 its reverse (1121110241353), we get a palindrome (4652530352564).
The spelling of 3531420111211 in words is "three trillion, five hundred thirty-one billion, four hundred twenty million, one hundred eleven thousand, two hundred eleven".
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