Search a number
-
+
354153434125011 = 31134027259423987
BaseRepresentation
bin101000010000110011100010…
…1101000110001001011010011
31201102221201220202011200200220
41100201213011220301023103
5332404422213114000021
63253115501441244123
7134411512150602003
oct12041470550611323
91642851822150626
10354153434125011
11a293169a891274
1233879384633643
131227c6aa7b61b1
146365190c62003
152ae25247a1cc6
hex14219c5a312d3

354153434125011 has 16 divisors (see below), whose sum is σ = 476501679590784. Its totient is φ = 233954776750464.

The previous prime is 354153434124983. The next prime is 354153434125013. The reversal of 354153434125011 is 110521434351453.

It is not a de Polignac number, because 354153434125011 - 210 = 354153434123987 is a prime.

It is not an unprimeable number, because it can be changed into a prime (354153434125013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128346841 + ... + 131077146.

It is an arithmetic number, because the mean of its divisors is an integer number (29781354974424).

Almost surely, 2354153434125011 is an apocalyptic number.

354153434125011 is a deficient number, since it is larger than the sum of its proper divisors (122348245465773).

354153434125011 is a wasteful number, since it uses less digits than its factorization.

354153434125011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259428130.

The product of its (nonzero) digits is 432000, while the sum is 42.

Adding to 354153434125011 its reverse (110521434351453), we get a palindrome (464674868476464).

The spelling of 354153434125011 in words is "three hundred fifty-four trillion, one hundred fifty-three billion, four hundred thirty-four million, one hundred twenty-five thousand, eleven".

Divisors: 1 3 113 339 4027 12081 455051 1365153 259423987 778271961 29314910531 87944731593 1044700395649 3134101186947 118051144708337 354153434125011