Base | Representation |
---|---|
bin | 101000010000110011100010… |
… | …1101000110001001011010011 |
3 | 1201102221201220202011200200220 |
4 | 1100201213011220301023103 |
5 | 332404422213114000021 |
6 | 3253115501441244123 |
7 | 134411512150602003 |
oct | 12041470550611323 |
9 | 1642851822150626 |
10 | 354153434125011 |
11 | a293169a891274 |
12 | 33879384633643 |
13 | 1227c6aa7b61b1 |
14 | 6365190c62003 |
15 | 2ae25247a1cc6 |
hex | 14219c5a312d3 |
354153434125011 has 16 divisors (see below), whose sum is σ = 476501679590784. Its totient is φ = 233954776750464.
The previous prime is 354153434124983. The next prime is 354153434125013. The reversal of 354153434125011 is 110521434351453.
It is not a de Polignac number, because 354153434125011 - 210 = 354153434123987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (354153434125013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128346841 + ... + 131077146.
It is an arithmetic number, because the mean of its divisors is an integer number (29781354974424).
Almost surely, 2354153434125011 is an apocalyptic number.
354153434125011 is a deficient number, since it is larger than the sum of its proper divisors (122348245465773).
354153434125011 is a wasteful number, since it uses less digits than its factorization.
354153434125011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 259428130.
The product of its (nonzero) digits is 432000, while the sum is 42.
Adding to 354153434125011 its reverse (110521434351453), we get a palindrome (464674868476464).
The spelling of 354153434125011 in words is "three hundred fifty-four trillion, one hundred fifty-three billion, four hundred thirty-four million, one hundred twenty-five thousand, eleven".
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