Base | Representation |
---|---|
bin | 110011101010011010010… |
… | …100010100001000101001 |
3 | 110120101202202212010202101 |
4 | 303222122110110020221 |
5 | 431131333343044423 |
6 | 11314542024533401 |
7 | 514332026054215 |
oct | 63523224241051 |
9 | 13511682763671 |
10 | 3550232003113 |
11 | 1149710458634 |
12 | 494085621261 |
13 | 1c9a297cb633 |
14 | c3b9159d945 |
15 | 6253a2987ad |
hex | 33a9a514229 |
3550232003113 has 16 divisors (see below), whose sum is σ = 3596383929600. Its totient is φ = 3504280665600.
The previous prime is 3550232002981. The next prime is 3550232003189. The reversal of 3550232003113 is 3113002320553.
3550232003113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3550232003113 - 221 = 3550229905961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3550232009113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137908423 + ... + 137934163.
It is an arithmetic number, because the mean of its divisors is an integer number (224773995600).
Almost surely, 23550232003113 is an apocalyptic number.
It is an amenable number.
3550232003113 is a deficient number, since it is larger than the sum of its proper divisors (46151926487).
3550232003113 is a wasteful number, since it uses less digits than its factorization.
3550232003113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29568.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 3550232003113 its reverse (3113002320553), we get a palindrome (6663234323666).
The spelling of 3550232003113 in words is "three trillion, five hundred fifty billion, two hundred thirty-two million, three thousand, one hundred thirteen".
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