Base | Representation |
---|---|
bin | 101101100110110010100000… |
… | …1001011101101010101111001 |
3 | 1221121101002000222000102201120 |
4 | 1123031211001023231111321 |
5 | 410040012111001031131 |
6 | 3541104114420135453 |
7 | 150332342066624103 |
oct | 13315450113552571 |
9 | 1847332028012646 |
10 | 401155334002041 |
11 | 106903026a45393 |
12 | 38baa711837589 |
13 | 142aba2a198b68 |
14 | 710c043a08573 |
15 | 3159e868a4496 |
hex | 16cd9412ed579 |
401155334002041 has 32 divisors (see below), whose sum is σ = 544479575040000. Its totient is φ = 262669984619328.
The previous prime is 401155334002009. The next prime is 401155334002121. The reversal of 401155334002041 is 140200433551104.
It is not a de Polignac number, because 401155334002041 - 25 = 401155334002009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 401155334001993 and 401155334002011.
It is not an unprimeable number, because it can be changed into a prime (401155334002441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 226111900 + ... + 227879138.
It is an arithmetic number, because the mean of its divisors is an integer number (17014986720000).
Almost surely, 2401155334002041 is an apocalyptic number.
It is an amenable number.
401155334002041 is a deficient number, since it is larger than the sum of its proper divisors (143324241037959).
401155334002041 is a wasteful number, since it uses less digits than its factorization.
401155334002041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1772333.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 401155334002041 its reverse (140200433551104), we get a palindrome (541355767553145).
The spelling of 401155334002041 in words is "four hundred one trillion, one hundred fifty-five billion, three hundred thirty-four million, two thousand, forty-one".
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