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4013202001011 = 371361140415031
BaseRepresentation
bin111010011001100101011…
…110101100110001110011
3112012122202221120211200120
4322121211132230301303
51011223014203013021
612311350050421323
7562641613111020
oct72314536546163
915178687524616
104013202001011
111307a979a6405
12549951291843
1323159bca5458
14dc35084c547
156e5d500e2c6
hex3a6657acc73

4013202001011 has 16 divisors (see below), whose sum is σ = 6119848754688. Its totient is φ = 2291573289600.

The previous prime is 4013202001009. The next prime is 4013202001051. The reversal of 4013202001011 is 1101002023104.

It is not a de Polignac number, because 4013202001011 - 21 = 4013202001009 is a prime.

It is a super-2 number, since 2×40132020010112 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4013202001051) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70178935 + ... + 70236096.

It is an arithmetic number, because the mean of its divisors is an integer number (382490547168).

Almost surely, 24013202001011 is an apocalyptic number.

4013202001011 is a deficient number, since it is larger than the sum of its proper divisors (2106646753677).

4013202001011 is a wasteful number, since it uses less digits than its factorization.

4013202001011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140416402.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 4013202001011 its reverse (1101002023104), we get a palindrome (5114204024115).

The spelling of 4013202001011 in words is "four trillion, thirteen billion, two hundred two million, one thousand, eleven".

Divisors: 1 3 7 21 1361 4083 9527 28581 140415031 421245093 982905217 2948715651 191104857191 573314571573 1337734000337 4013202001011