Base | Representation |
---|---|
bin | 111010011001100101011… |
… | …110101100110001110011 |
3 | 112012122202221120211200120 |
4 | 322121211132230301303 |
5 | 1011223014203013021 |
6 | 12311350050421323 |
7 | 562641613111020 |
oct | 72314536546163 |
9 | 15178687524616 |
10 | 4013202001011 |
11 | 1307a979a6405 |
12 | 549951291843 |
13 | 23159bca5458 |
14 | dc35084c547 |
15 | 6e5d500e2c6 |
hex | 3a6657acc73 |
4013202001011 has 16 divisors (see below), whose sum is σ = 6119848754688. Its totient is φ = 2291573289600.
The previous prime is 4013202001009. The next prime is 4013202001051. The reversal of 4013202001011 is 1101002023104.
It is not a de Polignac number, because 4013202001011 - 21 = 4013202001009 is a prime.
It is a super-2 number, since 2×40132020010112 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4013202001051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70178935 + ... + 70236096.
It is an arithmetic number, because the mean of its divisors is an integer number (382490547168).
Almost surely, 24013202001011 is an apocalyptic number.
4013202001011 is a deficient number, since it is larger than the sum of its proper divisors (2106646753677).
4013202001011 is a wasteful number, since it uses less digits than its factorization.
4013202001011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140416402.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 4013202001011 its reverse (1101002023104), we get a palindrome (5114204024115).
The spelling of 4013202001011 in words is "four trillion, thirteen billion, two hundred two million, one thousand, eleven".
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