4013541045433 has 32 divisors (see below), whose sum is σ = 4203296614400. Its totient is φ = 3828735060480.

The previous prime is 4013541045377. The next prime is 4013541045491. The reversal of 4013541045433 is 3345401453104.

4013541045433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 4013541045433 - 2¹³ = 4013541037241 is a prime.

It is a super-2 number, since 2×4013541045433² (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (37).

It is a junction number, because it is equal to n+sod(n) for n = 4013541045392 and 4013541045401.

It is not an unprimeable number, because it can be changed into a prime (4013541046433) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 742283416 + ... + 742288822.

It is an arithmetic number, because the mean of its divisors is an integer number (131353019200).

Almost surely, 2^{4013541045433} is an apocalyptic number.

It is an amenable number.

4013541045433 is a deficient number, since it is larger than the sum of its proper divisors (189755568967).

4013541045433 is a wasteful number, since it uses less digits than its factorization.

4013541045433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7097.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 4013541045433 its reverse (3345401453104), we get a palindrome (7358942498537).

The spelling of 4013541045433 in words is "four trillion, thirteen billion, five hundred forty-one million, forty-five thousand, four hundred thirty-three".