Base | Representation |
---|---|
bin | 111010101010100011100… |
… | …110111010110111010001 |
3 | 112021101210212220002110220 |
4 | 322222203212322313101 |
5 | 1012022324044244213 |
6 | 12324002151543253 |
7 | 564155310256602 |
oct | 72524346726721 |
9 | 15241725802426 |
10 | 4031424212433 |
11 | 1314798961572 |
12 | 55139798ab29 |
13 | 233214268b87 |
14 | dd19c99dda9 |
15 | 6eceeb5ce23 |
hex | 3aaa39badd1 |
4031424212433 has 16 divisors (see below), whose sum is σ = 5658222323520. Its totient is φ = 2546125275456.
The previous prime is 4031424212429. The next prime is 4031424212437. The reversal of 4031424212433 is 3342124241304.
It is an interprime number because it is at equal distance from previous prime (4031424212429) and next prime (4031424212437).
It is not a de Polignac number, because 4031424212433 - 22 = 4031424212429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4031424212394 and 4031424212403.
It is not an unprimeable number, because it can be changed into a prime (4031424212437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3694191 + ... + 4659387.
It is an arithmetic number, because the mean of its divisors is an integer number (353638895220).
Almost surely, 24031424212433 is an apocalyptic number.
It is an amenable number.
4031424212433 is a deficient number, since it is larger than the sum of its proper divisors (1626798111087).
4031424212433 is a wasteful number, since it uses less digits than its factorization.
4031424212433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1038496.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 4031424212433 its reverse (3342124241304), we get a palindrome (7373548453737).
The spelling of 4031424212433 in words is "four trillion, thirty-one billion, four hundred twenty-four million, two hundred twelve thousand, four hundred thirty-three".
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