411211314200041 has 16 divisors (see below), whose sum is σ = 414801368910720. Its totient is φ = 407635538705280.

The previous prime is 411211314200023. The next prime is 411211314200059. The reversal of 411211314200041 is 140002413112114.

It is an interprime number because it is at equal distance from previous prime (411211314200023) and next prime (411211314200059).

It is a cyclic number.

It is not a de Polignac number, because 411211314200041 - 2⁵ = 411211314200009 is a prime.

It is a super-2 number, since 2×411211314200041² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411211314199979 and 411211314200015.

It is not an unprimeable number, because it can be changed into a prime (411211314200081) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 424390066 + ... + 425357908.

It is an arithmetic number, because the mean of its divisors is an integer number (25925085556920).

Almost surely, 2^{411211314200041} is an apocalyptic number.

It is an amenable number.

411211314200041 is a deficient number, since it is larger than the sum of its proper divisors (3590054710679).

411211314200041 is a wasteful number, since it uses less digits than its factorization.

411211314200041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 975216.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 411211314200041 its reverse (140002413112114), we get a palindrome (551213727312155).

The spelling of 411211314200041 in words is "four hundred eleven trillion, two hundred eleven billion, three hundred fourteen million, two hundred thousand, forty-one".