Base | Representation |
---|---|
bin | 1011111110001000001… |
… | …10111010100100001011 |
3 | 1110022200001011112220210 |
4 | 11333010012322210023 |
5 | 23214331340241303 |
6 | 512542032252203 |
7 | 41500460441031 |
oct | 5770406724413 |
9 | 1408601145823 |
10 | 411312040203 |
11 | 149488a18659 |
12 | 6786b6a1063 |
13 | 2ca2c0bab5c |
14 | 15c9c69c551 |
15 | aa74a74203 |
hex | 5fc41ba90b |
411312040203 has 16 divisors (see below), whose sum is σ = 548862089600. Its totient is φ = 273985104960.
The previous prime is 411312040201. The next prime is 411312040207. The reversal of 411312040203 is 302040213114.
411312040203 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 411312040203 - 21 = 411312040201 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 411312040203.
It is not an unprimeable number, because it can be changed into a prime (411312040201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22370268 + ... + 22388646.
It is an arithmetic number, because the mean of its divisors is an integer number (34303880600).
Almost surely, 2411312040203 is an apocalyptic number.
411312040203 is a deficient number, since it is larger than the sum of its proper divisors (137550049397).
411312040203 is a wasteful number, since it uses less digits than its factorization.
411312040203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24042.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 411312040203 its reverse (302040213114), we get a palindrome (713352253317).
The spelling of 411312040203 in words is "four hundred eleven billion, three hundred twelve million, forty thousand, two hundred three".
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