Base | Representation |
---|---|
bin | 101110110000101101001001… |
… | …1111100101101011111000010 |
3 | 1222221100021011011220002211110 |
4 | 1131201122103330231133002 |
5 | 412402433211440000214 |
6 | 4014443105024024150 |
7 | 152431323202053051 |
oct | 13541322374553702 |
9 | 1887307134802743 |
10 | 411314320234434 |
11 | 10a06a4729149a1 |
12 | 3a16b579762056 |
13 | 14867a0a5433b6 |
14 | 737da0db58398 |
15 | 3284369284159 |
hex | 1761693f2d7c2 |
411314320234434 has 16 divisors (see below), whose sum is σ = 822650141376000. Its totient is φ = 137101189926960.
The previous prime is 411314320234393. The next prime is 411314320234453. The reversal of 411314320234434 is 434432023413114.
It is a junction number, because it is equal to n+sod(n) for n = 411314320234392 and 411314320234401.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 895622434 + ... + 896081565.
It is an arithmetic number, because the mean of its divisors is an integer number (51415633836000).
Almost surely, 2411314320234434 is an apocalyptic number.
411314320234434 is an abundant number, since it is smaller than the sum of its proper divisors (411335821141566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
411314320234434 is a wasteful number, since it uses less digits than its factorization.
411314320234434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1791742265.
The product of its (nonzero) digits is 331776, while the sum is 39.
Adding to 411314320234434 its reverse (434432023413114), we get a palindrome (845746343647548).
The spelling of 411314320234434 in words is "four hundred eleven trillion, three hundred fourteen billion, three hundred twenty million, two hundred thirty-four thousand, four hundred thirty-four".
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