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411314320234434 = 23382611791703999
BaseRepresentation
bin101110110000101101001001…
…1111100101101011111000010
31222221100021011011220002211110
41131201122103330231133002
5412402433211440000214
64014443105024024150
7152431323202053051
oct13541322374553702
91887307134802743
10411314320234434
1110a06a4729149a1
123a16b579762056
1314867a0a5433b6
14737da0db58398
153284369284159
hex1761693f2d7c2

411314320234434 has 16 divisors (see below), whose sum is σ = 822650141376000. Its totient is φ = 137101189926960.

The previous prime is 411314320234393. The next prime is 411314320234453. The reversal of 411314320234434 is 434432023413114.

It is a junction number, because it is equal to n+sod(n) for n = 411314320234392 and 411314320234401.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 895622434 + ... + 896081565.

It is an arithmetic number, because the mean of its divisors is an integer number (51415633836000).

Almost surely, 2411314320234434 is an apocalyptic number.

411314320234434 is an abundant number, since it is smaller than the sum of its proper divisors (411335821141566).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

411314320234434 is a wasteful number, since it uses less digits than its factorization.

411314320234434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1791742265.

The product of its (nonzero) digits is 331776, while the sum is 39.

Adding to 411314320234434 its reverse (434432023413114), we get a palindrome (845746343647548).

The spelling of 411314320234434 in words is "four hundred eleven trillion, three hundred fourteen billion, three hundred twenty million, two hundred thirty-four thousand, four hundred thirty-four".

Divisors: 1 2 3 6 38261 76522 114783 229566 1791703999 3583407998 5375111997 10750223994 68552386705739 137104773411478 205657160117217 411314320234434