Base | Representation |
---|---|
bin | 1011111111011011110… |
… | …10000100000001001010 |
3 | 1110101110220201221212220 |
4 | 11333231322010001022 |
5 | 23222300402022442 |
6 | 513135403114510 |
7 | 41524034246304 |
oct | 5775572040112 |
9 | 1411426657786 |
10 | 412013314122 |
11 | 149808858083 |
12 | 67a26512a36 |
13 | 2cb11485037 |
14 | 15d27888974 |
15 | aab63e8eec |
hex | 5fede8404a |
412013314122 has 16 divisors (see below), whose sum is σ = 841559110272. Its totient is φ = 134415691040.
The previous prime is 412013314109. The next prime is 412013314177. The reversal of 412013314122 is 221413310214.
412013314122 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 412013314092 and 412013314101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 730519779 + ... + 730520342.
It is an arithmetic number, because the mean of its divisors is an integer number (52597444392).
Almost surely, 2412013314122 is an apocalyptic number.
412013314122 is an abundant number, since it is smaller than the sum of its proper divisors (429545796150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
412013314122 is a wasteful number, since it uses less digits than its factorization.
412013314122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1461040173.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 412013314122 its reverse (221413310214), we get a palindrome (633426624336).
The spelling of 412013314122 in words is "four hundred twelve billion, thirteen million, three hundred fourteen thousand, one hundred twenty-two".
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