Base | Representation |
---|---|
bin | 111100011100001100011… |
… | …000011110111100000011 |
3 | 112201001202110020020000201 |
4 | 330130030120132330003 |
5 | 1021022221411320003 |
6 | 12500021533430031 |
7 | 606035100003160 |
oct | 74341430367403 |
9 | 15631673206021 |
10 | 4153441120003 |
11 | 136151226114a |
12 | 570b6b03b317 |
13 | 24188b26a276 |
14 | 105055b23067 |
15 | 73091c15b1d |
hex | 3c70c61ef03 |
4153441120003 has 16 divisors (see below), whose sum is σ = 4945705703424. Its totient is φ = 3413052074880.
The previous prime is 4153441120001. The next prime is 4153441120019. The reversal of 4153441120003 is 3000211443514.
4153441120003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4153441120003 - 21 = 4153441120001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4153441120001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89417350 + ... + 89463787.
It is an arithmetic number, because the mean of its divisors is an integer number (309106606464).
Almost surely, 24153441120003 is an apocalyptic number.
4153441120003 is a deficient number, since it is larger than the sum of its proper divisors (792264583421).
4153441120003 is a wasteful number, since it uses less digits than its factorization.
4153441120003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178881282.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 4153441120003 its reverse (3000211443514), we get a palindrome (7153652563517).
The spelling of 4153441120003 in words is "four trillion, one hundred fifty-three billion, four hundred forty-one million, one hundred twenty thousand, three".
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