Base | Representation |
---|---|
bin | 101111110000101110001000… |
… | …1001101001010000111010011 |
3 | 2001002111100211111000121210020 |
4 | 1133201130101031022013103 |
5 | 420031110412232021321 |
6 | 4045301005214034523 |
7 | 154330061516212425 |
oct | 13741342115120723 |
9 | 2032440744017706 |
10 | 420112514720211 |
11 | 111951798281305 |
12 | 3b1507531a8a43 |
13 | 15055595012cc1 |
14 | 75a57a8a4c815 |
15 | 3388155c444c6 |
hex | 17e171134a1d3 |
420112514720211 has 32 divisors (see below), whose sum is σ = 566413086520320. Its totient is φ = 276951443912064.
The previous prime is 420112514720209. The next prime is 420112514720231. The reversal of 420112514720211 is 112027415211024.
It is not a de Polignac number, because 420112514720211 - 21 = 420112514720209 is a prime.
It is a super-2 number, since 2×4201125147202112 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (420112514720231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7153622530 + ... + 7153681256.
It is an arithmetic number, because the mean of its divisors is an integer number (17700408953760).
Almost surely, 2420112514720211 is an apocalyptic number.
420112514720211 is a deficient number, since it is larger than the sum of its proper divisors (146300571800109).
420112514720211 is a wasteful number, since it uses less digits than its factorization.
420112514720211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92195.
The product of its (nonzero) digits is 8960, while the sum is 33.
Adding to 420112514720211 its reverse (112027415211024), we get a palindrome (532139929931235).
The spelling of 420112514720211 in words is "four hundred twenty trillion, one hundred twelve billion, five hundred fourteen million, seven hundred twenty thousand, two hundred eleven".
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