Base | Representation |
---|---|
bin | 111101101110000010100… |
… | …011011000001000100001 |
3 | 120000110121002112222011202 |
4 | 331232002203120020201 |
5 | 1023442212144024441 |
6 | 13004234212050545 |
7 | 615265636642256 |
oct | 75560243301041 |
9 | 16013532488152 |
10 | 4241323033121 |
11 | 139580a310209 |
12 | 585bb6603a55 |
13 | 249c5530aca5 |
14 | 1093d15c742d |
15 | 754d715619b |
hex | 3db828d8221 |
4241323033121 has 16 divisors (see below), whose sum is σ = 4469984688000. Its totient is φ = 4013207762688.
The previous prime is 4241323033109. The next prime is 4241323033193. The reversal of 4241323033121 is 1213303231424.
4241323033121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4241323033121 - 218 = 4241322770977 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4241323033421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53544281 + ... + 53623433.
It is an arithmetic number, because the mean of its divisors is an integer number (279374043000).
Almost surely, 24241323033121 is an apocalyptic number.
It is an amenable number.
4241323033121 is a deficient number, since it is larger than the sum of its proper divisors (228661654879).
4241323033121 is a wasteful number, since it uses less digits than its factorization.
4241323033121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82568.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4241323033121 its reverse (1213303231424), we get a palindrome (5454626264545).
The spelling of 4241323033121 in words is "four trillion, two hundred forty-one billion, three hundred twenty-three million, thirty-three thousand, one hundred twenty-one".
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