Base | Representation |
---|---|
bin | 111110100100101101111… |
… | …111111100110111100001 |
3 | 120020002010202121020012110 |
4 | 332210231333330313201 |
5 | 1030422432201034101 |
6 | 13051224111545533 |
7 | 622444564644024 |
oct | 76445577746741 |
9 | 16202122536173 |
10 | 4300034002401 |
11 | 14086a8102425 |
12 | 59546082b2a9 |
13 | 2526509a0cb7 |
14 | 10c1a0bb31bb |
15 | 76cc1633cd6 |
hex | 3e92dffcde1 |
4300034002401 has 16 divisors (see below), whose sum is σ = 5934452645888. Its totient is φ = 2766656293200.
The previous prime is 4300034002393. The next prime is 4300034002409. The reversal of 4300034002401 is 1042004300034.
It is an interprime number because it is at equal distance from previous prime (4300034002393) and next prime (4300034002409).
It is not a de Polignac number, because 4300034002401 - 23 = 4300034002393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4300034002409) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62958955 + ... + 63027216.
It is an arithmetic number, because the mean of its divisors is an integer number (370903290368).
Almost surely, 24300034002401 is an apocalyptic number.
It is an amenable number.
4300034002401 is a deficient number, since it is larger than the sum of its proper divisors (1634418643487).
4300034002401 is a wasteful number, since it uses less digits than its factorization.
4300034002401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125986572.
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 4300034002401 its reverse (1042004300034), we get a palindrome (5342038302435).
The spelling of 4300034002401 in words is "four trillion, three hundred billion, thirty-four million, two thousand, four hundred one".
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