Base | Representation |
---|---|
bin | 111110100111110001100… |
… | …001110010110100001001 |
3 | 120020101121101022021120220 |
4 | 332213301201302310021 |
5 | 1031001141443244431 |
6 | 13052525414540253 |
7 | 622622100064350 |
oct | 76476141626411 |
9 | 16211541267526 |
10 | 4303314431241 |
11 | 140a03089a141 |
12 | 596017367689 |
13 | 252a544c0157 |
14 | 10c3d2736997 |
15 | 76e1461cb96 |
hex | 3e9f1872d09 |
4303314431241 has 32 divisors (see below), whose sum is σ = 6560799879168. Its totient is φ = 2457774109440.
The previous prime is 4303314431239. The next prime is 4303314431321. The reversal of 4303314431241 is 1421344133034.
4303314431241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4303314431241 - 21 = 4303314431239 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4303314431341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 618200001 + ... + 618206961.
It is an arithmetic number, because the mean of its divisors is an integer number (205024996224).
Almost surely, 24303314431241 is an apocalyptic number.
It is an amenable number.
4303314431241 is a deficient number, since it is larger than the sum of its proper divisors (2257485447927).
4303314431241 is a wasteful number, since it uses less digits than its factorization.
4303314431241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17861.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 4303314431241 its reverse (1421344133034), we get a palindrome (5724658564275).
The spelling of 4303314431241 in words is "four trillion, three hundred three billion, three hundred fourteen million, four hundred thirty-one thousand, two hundred forty-one".
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