Base | Representation |
---|---|
bin | 10011100111010111101110… |
… | …11001000100101001101001 |
3 | 12122201120221101222222110022 |
4 | 21303223313121010221221 |
5 | 21123202331301201213 |
6 | 231423330011330225 |
7 | 12041225662433543 |
oct | 1163536731045151 |
9 | 178646841888408 |
10 | 43134212131433 |
11 | 12820131272635 |
12 | 4a07848450975 |
13 | 1b0b700834947 |
14 | a919c8050693 |
15 | 4ec046e9d308 |
hex | 273af7644a69 |
43134212131433 has 16 divisors (see below), whose sum is σ = 43713239348352. Its totient is φ = 42559369920000.
The previous prime is 43134212131429. The next prime is 43134212131471. The reversal of 43134212131433 is 33413121243134.
It is a cyclic number.
It is not a de Polignac number, because 43134212131433 - 22 = 43134212131429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43134212131393 and 43134212131402.
It is not an unprimeable number, because it can be changed into a prime (43134212131403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39357113 + ... + 40438233.
It is an arithmetic number, because the mean of its divisors is an integer number (2732077459272).
Almost surely, 243134212131433 is an apocalyptic number.
It is an amenable number.
43134212131433 is a deficient number, since it is larger than the sum of its proper divisors (579027216919).
43134212131433 is a wasteful number, since it uses less digits than its factorization.
43134212131433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1083056.
The product of its digits is 62208, while the sum is 35.
Adding to 43134212131433 its reverse (33413121243134), we get a palindrome (76547333374567).
The spelling of 43134212131433 in words is "forty-three trillion, one hundred thirty-four billion, two hundred twelve million, one hundred thirty-one thousand, four hundred thirty-three".
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