Base | Representation |
---|---|
bin | 111110111000010111100… |
… | …110010111101110100011 |
3 | 120022002121012011002221011 |
4 | 332320113212113232203 |
5 | 1031244140024100103 |
6 | 13105033501241351 |
7 | 624122463522613 |
oct | 76702746275643 |
9 | 16262535132834 |
10 | 4321133034403 |
11 | 1416644a45459 |
12 | 59956a863257 |
13 | 254633c7ab13 |
14 | 10d203024a43 |
15 | 77608ae3d6d |
hex | 3ee17997ba3 |
4321133034403 has 16 divisors (see below), whose sum is σ = 4383767044800. Its totient is φ = 4258593722880.
The previous prime is 4321133034373. The next prime is 4321133034457. The reversal of 4321133034403 is 3044303311234.
4321133034403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4321133034403 - 25 = 4321133034371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4321133034473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 923514018 + ... + 923518696.
It is an arithmetic number, because the mean of its divisors is an integer number (273985440300).
Almost surely, 24321133034403 is an apocalyptic number.
4321133034403 is a deficient number, since it is larger than the sum of its proper divisors (62634010397).
4321133034403 is a wasteful number, since it uses less digits than its factorization.
4321133034403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11982.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 4321133034403 its reverse (3044303311234), we get a palindrome (7365436345637).
The spelling of 4321133034403 in words is "four trillion, three hundred twenty-one billion, one hundred thirty-three million, thirty-four thousand, four hundred three".
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