Base | Representation |
---|---|
bin | 111111000010001000111… |
… | …111111011000000000001 |
3 | 120100002200102120012112121 |
4 | 333002020333323000001 |
5 | 1031432132111224411 |
6 | 13113530555124241 |
7 | 624643501120450 |
oct | 77021077730001 |
9 | 16302612505477 |
10 | 4331625492481 |
11 | 1420039735511 |
12 | 59b5b8743681 |
13 | 2556169ac5b1 |
14 | 10d91a738b97 |
15 | 77a1ed2a571 |
hex | 3f088ffb001 |
4331625492481 has 16 divisors (see below), whose sum is σ = 5043931699968. Its totient is φ = 3642697656000.
The previous prime is 4331625492461. The next prime is 4331625492517. The reversal of 4331625492481 is 1842945261334.
It is a cyclic number.
It is not a de Polignac number, because 4331625492481 - 215 = 4331625459713 is a prime.
It is a super-2 number, since 2×43316254924812 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4331625492431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28975116 + ... + 29124226.
It is an arithmetic number, because the mean of its divisors is an integer number (315245731248).
Almost surely, 24331625492481 is an apocalyptic number.
It is an amenable number.
4331625492481 is a deficient number, since it is larger than the sum of its proper divisors (712306207487).
4331625492481 is a wasteful number, since it uses less digits than its factorization.
4331625492481 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 227472.
The product of its digits is 4976640, while the sum is 52.
The spelling of 4331625492481 in words is "four trillion, three hundred thirty-one billion, six hundred twenty-five million, four hundred ninety-two thousand, four hundred eighty-one".
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