Base | Representation |
---|---|
bin | 1100100110111001111… |
… | …11000010001011100001 |
3 | 1112102011202012120212000 |
4 | 12103130333002023201 |
5 | 24044200241203441 |
6 | 531002234154213 |
7 | 43204130202501 |
oct | 6233477021341 |
9 | 1472152176760 |
10 | 433204241121 |
11 | 1577a2556193 |
12 | 6bb5b282969 |
13 | 31b0a7c84b2 |
14 | 16d77dbba01 |
15 | b4069ac2b6 |
hex | 64dcfc22e1 |
433204241121 has 16 divisors (see below), whose sum is σ = 659129577600. Its totient is φ = 280997344944.
The previous prime is 433204241101. The next prime is 433204241137. The reversal of 433204241121 is 121142402334.
433204241121 is a `hidden beast` number, since 43 + 3 + 204 + 2 + 411 + 2 + 1 = 666.
It is not a de Polignac number, because 433204241121 - 214 = 433204224737 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (433204241101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216817941 + ... + 216819938.
It is an arithmetic number, because the mean of its divisors is an integer number (41195598600).
Almost surely, 2433204241121 is an apocalyptic number.
It is an amenable number.
433204241121 is a deficient number, since it is larger than the sum of its proper divisors (225925336479).
433204241121 is a wasteful number, since it uses less digits than its factorization.
433204241121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433637925 (or 433637919 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 433204241121 its reverse (121142402334), we get a palindrome (554346643455).
The spelling of 433204241121 in words is "four hundred thirty-three billion, two hundred four million, two hundred forty-one thousand, one hundred twenty-one".
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