Base | Representation |
---|---|
bin | 10011101101000100011111… |
… | …01001100101011010111010 |
3 | 12200102022101222220210012011 |
4 | 21312202033221211122322 |
5 | 21134404410233000424 |
6 | 232053313505040134 |
7 | 12061330534061041 |
oct | 1166421751453272 |
9 | 180368358823164 |
10 | 43330040125114 |
11 | 12896192047726 |
12 | 4a3979a92604a |
13 | 1b2400b6c9b12 |
14 | a9b284005558 |
15 | 5021a9022694 |
hex | 27688fa656ba |
43330040125114 has 16 divisors (see below), whose sum is σ = 66833462646720. Its totient is φ = 21056237609440.
The previous prime is 43330040125079. The next prime is 43330040125123. The reversal of 43330040125114 is 41152104003334.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1004569924 + ... + 1004613055.
It is an arithmetic number, because the mean of its divisors is an integer number (4177091415420).
Almost surely, 243330040125114 is an apocalyptic number.
43330040125114 is a deficient number, since it is larger than the sum of its proper divisors (23503422521606).
43330040125114 is a wasteful number, since it uses less digits than its factorization.
43330040125114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2009183285.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 43330040125114 its reverse (41152104003334), we get a palindrome (84482144128448).
The spelling of 43330040125114 in words is "forty-three trillion, three hundred thirty billion, forty million, one hundred twenty-five thousand, one hundred fourteen".
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