Base | Representation |
---|---|
bin | 111111001010001111100… |
… | …010011101101000101011 |
3 | 120100221010201111100110000 |
4 | 333022033202131220223 |
5 | 1032102441214121011 |
6 | 13121530130554043 |
7 | 625402206004323 |
oct | 77121742355053 |
9 | 16327121440400 |
10 | 4340325145131 |
11 | 14237a3435298 |
12 | 5a1226138923 |
13 | 2563a216c961 |
14 | 110103cca283 |
15 | 77d7d97a356 |
hex | 3f28f89da2b |
4340325145131 has 10 divisors (see below), whose sum is σ = 6483695587292. Its totient is φ = 2893550096700.
The previous prime is 4340325145129. The next prime is 4340325145153. The reversal of 4340325145131 is 1315415230434.
4340325145131 is a `hidden beast` number, since 4 + 3 + 4 + 0 + 3 + 2 + 514 + 5 + 131 = 666.
It is not a de Polignac number, because 4340325145131 - 21 = 4340325145129 is a prime.
It is a super-2 number, since 2×43403251451312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4340325145531) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 26792130445 + ... + 26792130606.
Almost surely, 24340325145131 is an apocalyptic number.
4340325145131 is a deficient number, since it is larger than the sum of its proper divisors (2143370442161).
4340325145131 is an equidigital number, since it uses as much as digits as its factorization.
4340325145131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53584261063 (or 53584261054 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
The spelling of 4340325145131 in words is "four trillion, three hundred forty billion, three hundred twenty-five million, one hundred forty-five thousand, one hundred thirty-one".
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