Base | Representation |
---|---|
bin | 110001010110100100110110… |
… | …1100101110101101000001001 |
3 | 2002221001122022021222210021210 |
4 | 1202231021231211311220021 |
5 | 423344440032424031213 |
6 | 4135140001310123333 |
7 | 160303340160222150 |
oct | 14255115545655011 |
9 | 2087048267883253 |
10 | 434111363111433 |
11 | 1163596602421a7 |
12 | 408318351b0549 |
13 | 1582c6ab4b6827 |
14 | 792b160186597 |
15 | 352c3759b50c3 |
hex | 18ad26d975a09 |
434111363111433 has 32 divisors (see below), whose sum is σ = 668962566132480. Its totient is φ = 245266534149120.
The previous prime is 434111363111383. The next prime is 434111363111467. The reversal of 434111363111433 is 334111363111434.
It is not a de Polignac number, because 434111363111433 - 28 = 434111363111177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 434111363111391 and 434111363111400.
It is not an unprimeable number, because it can be changed into a prime (434111363111533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41909013 + ... + 51230733.
It is an arithmetic number, because the mean of its divisors is an integer number (20905080191640).
Almost surely, 2434111363111433 is an apocalyptic number.
It is an amenable number.
434111363111433 is a deficient number, since it is larger than the sum of its proper divisors (234851203021047).
434111363111433 is a wasteful number, since it uses less digits than its factorization.
434111363111433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9346737.
The product of its digits is 93312, while the sum is 39.
Subtracting from 434111363111433 its reverse (334111363111434), we obtain a palindrome (99999999999999).
The spelling of 434111363111433 in words is "four hundred thirty-four trillion, one hundred eleven billion, three hundred sixty-three million, one hundred eleven thousand, four hundred thirty-three".
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