Base | Representation |
---|---|
bin | 10011101111011101111011… |
… | …11001001110000111010001 |
3 | 12200201012001012212001002112 |
4 | 21313232331321032013101 |
5 | 21142232114102321023 |
6 | 232155220211155105 |
7 | 12100305150344000 |
oct | 1167567571160721 |
9 | 180635035761075 |
10 | 43412420354513 |
11 | 12918116592341 |
12 | 4a5174b8a5a95 |
13 | 1b2ba099b76a2 |
14 | aa125ad34c37 |
15 | 5043cb45e478 |
hex | 277bbde4e1d1 |
43412420354513 has 32 divisors (see below), whose sum is σ = 50716849305600. Its totient is φ = 37144467032400.
The previous prime is 43412420354441. The next prime is 43412420354521. The reversal of 43412420354513 is 31545302421434.
It is not a de Polignac number, because 43412420354513 - 216 = 43412420288977 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (43412420354543) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 440833706 + ... + 440932172.
It is an arithmetic number, because the mean of its divisors is an integer number (1584901540800).
Almost surely, 243412420354513 is an apocalyptic number.
It is an amenable number.
43412420354513 is a deficient number, since it is larger than the sum of its proper divisors (7304428951087).
43412420354513 is a wasteful number, since it uses less digits than its factorization.
43412420354513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100762 (or 100748 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 43412420354513 its reverse (31545302421434), we get a palindrome (74957722775947).
The spelling of 43412420354513 in words is "forty-three trillion, four hundred twelve billion, four hundred twenty million, three hundred fifty-four thousand, five hundred thirteen".
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